原 lambda表达式对list中的中文进行排序

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需求：我们对list中的username字段进行排序，要求按照中文的首字母进行排序

一：代码如下

public static void main(String[] args) {
        List<User> dataList=new ArrayList<>();

        User u1=new User();
        u1.setUserName("张无忌");
        u1.setMobile("13248254444");

        User u2=new User();
        u2.setUserName("阿三");
        u2.setMobile("13248254444");

        User u3=new User();
        u3.setUserName("曹操");
        u3.setMobile("13248254444");

        dataList.add(u1);
        dataList.add(u2);
        dataList.add(u3);

        System.out.println("排序前：" + dataList);

        Comparator<Object> chinese=Collator.getInstance(Locale.CHINA);
        Collections.sort(dataList, (v1, v2) ->
            chinese.compare(v1.getUserName(), v2.getUserName())
        );

        System.out.println("排序后：" + dataList);
}

执行结果：

排序前：[User(userId=null, userName=张无忌, nickName=null, password=null, email=null, mobile=13248254444, position=null, dept=null, avatarUrl=null, status=null, customerType=null, createTime=null, updateTime=null), User(userId=null, userName=阿三, nickName=null, password=null, email=null, mobile=13248254444, position=null, dept=null, avatarUrl=null, status=null, customerType=null, createTime=null, updateTime=null), User(userId=null, userName=曹操, nickName=null, password=null, email=null, mobile=13248254444, position=null, dept=null, avatarUrl=null, status=null, customerType=null, createTime=null, updateTime=null)]
排序后：[User(userId=null, userName=阿三, nickName=null, password=null, email=null, mobile=13248254444, position=null, dept=null, avatarUrl=null, status=null, customerType=null, createTime=null, updateTime=null), User(userId=null, userName=曹操, nickName=null, password=null, email=null, mobile=13248254444, position=null, dept=null, avatarUrl=null, status=null, customerType=null, createTime=null, updateTime=null), User(userId=null, userName=张无忌, nickName=null, password=null, email=null, mobile=13248254444, position=null, dept=null, avatarUrl=null, status=null, customerType=null, createTime=null, updateTime=null)]